GaryMorris 0 Posted February 24, 2006 Share Posted February 24, 2006 Question: You are in a room with three light switches. Waaay down the hall is a light bulb that one of these switches controls. You can't see the other room or the light from the other room from the room you are in.All three light switches are off and the light bulb is also off. Now, you can fiddle with the light switches any way you want. Then, you can go into the room down the hall where the light bulb is and come back to the original room where the switches are.There is one specific way you'll know for certain which switch controls that light bulb.Answer: Easily enough, just turn two of the light switches on. Wait a while, and then turn one of them off, then quickly enter the room. One light will be on, one off, and one off but still hot. Link to post Share on other sites
turd ferguson 1 Posted February 24, 2006 Share Posted February 24, 2006 http://www.fullcontactpoker.com/poker-foru...showtopic=51426 Link to post Share on other sites
ShakeZuma 585 Posted February 24, 2006 Share Posted February 24, 2006 http://www.fullcontactpoker.com/poker-foru...showtopic=51426you smug son of a bitch.http://www.fullcontactpoker.com/poker-foru...hp?showforum=33 Link to post Share on other sites
sixhands 0 Posted February 25, 2006 Share Posted February 25, 2006 Very clever, okay here's another one for you guys.What is the most amount of change you can carry without having change for a dollar? Link to post Share on other sites
chrozzo 19 Posted February 25, 2006 Share Posted February 25, 2006 Very clever, okay here's another one for you guys.What is the most amount of change you can carry without having change for a dollar?ummmm.....99 pennies, or is this a trick question? Link to post Share on other sites
violaman 0 Posted February 25, 2006 Share Posted February 25, 2006 Wrong!Good lord you completely overlooked the wording of the riddleQuestion: You are in a room with three light switches. Waaay down the hall is a light bulb that one of these switches controls. You can't see the other room or the light from the other room from the room you are in.Easily enough, just turn two of the light switches on. Wait a while, and then turn one of them off, then quickly enter the room. One light will be on, one off, and one off but still hot.Light bulb in the question is singular, there is only one light! You can feel whether it was hot but it won't matter. I'm still working on this one but that is certainly not the answer. Link to post Share on other sites
Bubba83 0 Posted February 25, 2006 Share Posted February 25, 2006 It is the answer, he just explained it wrong. Basically, turn switch #1 on, wait 5 minutes, then turn switch #1 off, and turn switch #2 on.Then proceed down the hall quickly. Observe the light bulb. If the bulb is off, but warm, then switch #1 controls the bulb.If the bulb is on, switch #2 controls the bulb.If the bulb is off, and cold, then it must be switch #3 that controls the bulb. Link to post Share on other sites
yahaw 0 Posted February 25, 2006 Share Posted February 25, 2006 Very clever, okay here's another one for you guys.What is the most amount of change you can carry without having change for a dollar?$1.19 Link to post Share on other sites
digitalmonkey 929 Posted February 25, 2006 Share Posted February 25, 2006 Very clever, okay here's another one for you guys.What is the most amount of change you can carry without having change for a dollar?The answer to this is only limited by the number of toonies one can carry. Link to post Share on other sites
digitalmonkey 929 Posted February 25, 2006 Share Posted February 25, 2006 $1.193 quarters4 dimes4 pennies Link to post Share on other sites
kingtim 0 Posted February 28, 2006 Share Posted February 28, 2006 Very clever, okay here's another one for you guys.What is the most amount of change you can carry without having change for a dollar?my guess is 1.693 quarters9 dimes4 pennies Link to post Share on other sites
xtxoxpxd 0 Posted March 1, 2006 Share Posted March 1, 2006 my guess is 1.693 quarters9 dimes4 pennies 2 quarters and 5 dimes = ? Link to post Share on other sites
malaise_monk 0 Posted March 2, 2006 Share Posted March 2, 2006 This one's fun:There's an evil queen with a plan to execute 50 prisoners. She gathers them together and announces the plan:The prisoners will line up, all facing one direction so the one in back can see the other 49, and the one at the front can see no one. Starting at the back, each prisoner will be given a white or black hat at random (there could be 50 black hats, 50 white hats, or 25 of each). Each prisoner will be able to see the hats of the prisoners in front of him, but not his own hat or the hats of those behind him.After they all have hats, the queen will start at the back (with the prisoner who can see the other 49 hats) and ask each in turn for the color of the hat on his own head. The other prisoners hear the answer.If any prisoner talks, turns to look at hats of those behind him, or tries to look at the color of his own hat, all the prisoners will be killed. (Cheating is not an option.)Before carrying out the plan, the queen then leaves to let the prisoners discuss strategy for a while.---What strategy (if they thought of it in time) could the prisoners use to minimize the number of expected casualties among them, and what's the greatest number of prisoners the queen might be able to kill?For instance, if they agree not to use any strategy, they might as well have no discussion time. The queen could then expect to kill 25 of them on average, and might be able to kill all 50 if they get very unlucky.If the queen listens to their optimal strategy, can she do anything (like carefully selecting the hats) so that she statistically expects to kill more of them? If so, is there a different optimal strategy if the queen overhears their plan?Does it matter if the queen immediately kills those who answer incorrectly? Can she kill more prisoners when she doesn't give any indication of correct answers and waits until they've all given an answer before beginning the executions?Does it matter if the 50 prisoners are all enemies of each other and want to see the others die? What if that's almost true, but each prisoner has at least one friend he wants to save? Does it matter if they have to stay in order and can't look at their own hats, but can look at the prisoners and hats behind them? Link to post Share on other sites
kingtim 0 Posted March 2, 2006 Share Posted March 2, 2006 my guess is 1.693 quarters9 dimes4 penniesgood point Link to post Share on other sites
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