Texas Hold Em Aa V Aa Odds Question.

[Init2WINitHI 0]

Ok so I'm a little drunk in Vegas at Palazzo and needing to kill some time so I sit down at this table game called Texas Hold Em somethingoranother. How it works is everyone playing antes and gets two cards down. You look at your two cards and decide if you are going to play - All you have to do to win is beat the dealer. If you are going to play the hand you have to fill the first slot with 2x your ante. If not you fold and lose your ante. Once you see the flop you can check or bet = the ante, dealer then burns and turns, another round of betting then you are done. Dealer turns over his cards and you see if you beat him. Certain hands like straights etc pay higher payouts... all that being said has nothing to do with the issue. The issue is there is a bonus that you can play for any amount equal or greater than ante. It has payouts for an Ace and A Face that pay regardless of whether or not you beat the dealer. It pays out 30 to one if you have AA. It pays out 3000 to one if both you and the dealer have AA. So we get into a discussion about what the real odds are that you both would have AA. Me being drunk - a little - can't quite figure it out. The other drunk guy at the table tells me it is 212 to one times 212 to one. I tell him it can't be the exact same, because you have taken 2 aces out of the deck. But now I am back home, and sober and I still can't seem to get my brain to work the math on the odds of both one player and the dealer being dealt the same hand AA. Anyone that can help it would be appreciated. It is really bugging me.

[hank213 1,823]

4/52*3/51*2/50*1/49?