poker_study 0 Posted October 5, 2005 Share Posted October 5, 2005 So, how likely is it that 2 players, both of whom using both their hole cards will make a straight flush on a 3 suit board? :shock: Link to post Share on other sites
skoal_dip 0 Posted October 5, 2005 Share Posted October 5, 2005 if you both have suited connectors 3 apart, its about 9 percent. Link to post Share on other sites
The Enforcer 0 Posted October 5, 2005 Share Posted October 5, 2005 if you both have suited connectors 3 apart, its about 9 percent.What??? 9%? It must be a fraction of a percent at best. How do you get 9%? Link to post Share on other sites
ThePokerJew 0 Posted October 5, 2005 Share Posted October 5, 2005 if you both have suited connectors 3 apart, its about 9 percent.What??? 9%? It must be a fraction of a percent at best. How do you get 9%?He was joking. Link to post Share on other sites
skoal_dip 0 Posted October 5, 2005 Share Posted October 5, 2005 if you both have suited connectors 3 apart, its about 9 percent.What??? 9%? It must be a fraction of a percent at best. How do you get 9%?He was joking.Ummmmm..... no..... :wink: Link to post Share on other sites
KTW 0 Posted October 5, 2005 Share Posted October 5, 2005 If think the OP means a hand like: Player 1 holds 7h-8h and Player 2 holds 2h-3h and the flop is 4h-5h-6h.... It is @5,000 : 1 against flopping just ONE SF. Link to post Share on other sites
TheWynn 0 Posted October 5, 2005 Share Posted October 5, 2005 So, how likely is it that 2 players, both of whom using both their hole cards will make a straight flush on a 3 suit board? :shock:On pokerstars about 3 times every hour. Link to post Share on other sites
case ace 0 Posted October 5, 2005 Share Posted October 5, 2005 i believe its51*50*49*48*47*46 / 4 (for the 4 suits) in 1edit: plus your turn/river redraw (1.04) and the amount of possible str8 fushes (10) and the possible semi deals for two players at a ten player table (5)so its51*50*49*48*47*46* 1.04/ 10/ 4 /5 in 1or one in 60 million roughlysound about right? Link to post Share on other sites
posoo 0 Posted October 5, 2005 Share Posted October 5, 2005 Do you want to calculate:1). The probability that two players ACTUALLY HOLD two hands that can make a straight flush on the same board, and then do so?2). The probability of two players who hold (as a given) suited connectors with exactly three gaps (45 vs. T9 on a 678 board) actually doing so?3). The probability of two players who hold any two suited card that can make any straight flush (J9 vs. 65 on a 789 board)?These questions illustrate how nonsensical such a brief post is. Regardless of what you were looking for (I am certain that you, yourself do not know), the number will be very large, involving more powers of ten than you knew existed.Blessings,Posoo Link to post Share on other sites
Scanner313 0 Posted October 5, 2005 Share Posted October 5, 2005 Highly unlikely! Doesn't that say enough? Link to post Share on other sites
speedz99 145 Posted October 5, 2005 Share Posted October 5, 2005 6,876,076 - 1Duh. Doyle goes over this in SS2, didn't you guys read it? Link to post Share on other sites
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now