using the natural logarithm to determine points

[ANJBerg 0]

I run a league that uses a point system to pay off the overall winners. We play 12 events a year and players currently accumulate points based on their finish. Ex. 20 people in the tournament, 1st gets 20, last gets 1. This seemed to work, but if you miss 1 tournament you are screwed. I have been reading about the Natural Logarithm and was wondering if someone could give me a practical example of how this works. All I am finding online is an explanation but I would like to see a number worked out and how to get there so that I can understand it. Not a math wiz here.Any help would be appreciated.ANJ

[AceyDeucy 0]

Search Google Archive for Barbara Yoon's posts on rec.gambling.poker.Be sure to include logarithm. Otherwise you will get caught up in her other posts. Be sure to ingore anything with the word "blooop."

[ANJBerg 0]

Search Google Archive for Barbara Yoon's posts on rec.gambling.poker.Be sure to include logarithm. Otherwise you will get caught up in her other posts. Be sure to ingore anything with the word "blooop."

Any link? Having trouble finding anything

[Marc-O 0]

Let's talk about square roots first. If you have an equationX^2 = 4then X = squareroot(4) = 2If we haveX^2 = 3.8then X = squareroot(3. 8) which we need a calculator orslide rule to find a numerical approximation to X (about 1.94936).Now, to logarithms. If you have an equation2^X = 4then X = logbase2(4) = 2If we have an equation10^X = 100then X = logbase10(100) = 2 (because 10^2 = 100).There is a number called e which, like pi, pops up a lot inmathematics. The logbasee is called the "natural logarithm."So, sometimes you have an equatione^X = 100 to solve.From a calculator or slide rule, we can figure out thatX = logbasee(100) = 4.60517...because e, which equals about 2.7182818... to the power 4.60517...equals 100! (try it on a calculator and see!)Sometimes the natural logarithm is indicated by ln and the base tenlogarithm by log. so 10^x = 100; x = log(100) = 2;e^X = 100; X = ln(100) = 4.60517...

[PMJackson21 0]

Search Google Archive for Barbara Yoon's posts on rec.gambling.poker.Be sure to include logarithm. Otherwise you will get caught up in her other posts. Be sure to ingore anything with the word "blooop."

Sadly, Barbara (or 'her' real name, W. Lawrence Hill) passed away a few months back, but one could never go wrong reading 'her' old posts in the archives.Patrick

[dna4ever 2]

I use the standard TLB point structure for the points leaderboard in the Negreanu Open. Points = 10 * [sqrt(n)/sqrt(k)] * [1+log(b+0.25)]Where:n is the number of entrants k is the place of finish (k=1 for the first-place finisher, and so on) b is the buy-in amount in dollars (excluding administrative fee)Example: A player takes third place in a $20 tournament with a field of 150 players. Here:n = 150, k=3, b=20 The total points awarded to this player are:= 10 * [sqrt(n)/sqrt(k)] * [1+log(b+0.25)] = 10 * [sqrt(150)/sqrt(3)] * [1+log(20+0.25)] = 10 * sqrt(50) * (1+1.31) = 10 * 7.071 * 2.31 = 163.09 (rounded up)

[nutzbuster 7]

Let's talk about square roots first. If you have an equationX^2 = 4then X = squareroot(4) = 2If we haveX^2 = 3.8then X = squareroot(3. 8) which we need a calculator orslide rule to find a numerical approximation to X (about 1.94936).Now, to logarithms. If you have an equation2^X = 4then X = logbase2(4) = 2If we have an equation10^X = 100then X = logbase10(100) = 2 (because 10^2 = 100).There is a number called e which, like pi, pops up a lot inmathematics. The logbasee is called the "natural logarithm."So, sometimes you have an equatione^X = 100 to solve.From a calculator or slide rule, we can figure out thatX = logbasee(100) = 4.60517...because e, which equals about 2.7182818... to the power 4.60517...equals 100! (try it on a calculator and see!)Sometimes the natural logarithm is indicated by ln and the base tenlogarithm by log. so 10^x = 100; x = log(100) = 2;e^X = 100; X = ln(100) = 4.60517...

This is a joke, right?zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzBest...

[ANJBerg 0]

Let's talk about square roots first. If you have an equationX^2 = 4then X = squareroot(4) = 2If we haveX^2 = 3.8then X = squareroot(3. 8) which we need a calculator orslide rule to find a numerical approximation to X (about 1.94936).Now, to logarithms. If you have an equation2^X = 4then X = logbase2(4) = 2If we have an equation10^X = 100then X = logbase10(100) = 2 (because 10^2 = 100).There is a number called e which, like pi, pops up a lot inmathematics. The logbasee is called the "natural logarithm."So, sometimes you have an equatione^X = 100 to solve.From a calculator or slide rule, we can figure out thatX = logbasee(100) = 4.60517...because e, which equals about 2.7182818... to the power 4.60517...equals 100! (try it on a calculator and see!)Sometimes the natural logarithm is indicated by ln and the base tenlogarithm by log. so 10^x = 100; x = log(100) = 2;e^X = 100; X = ln(100) = 4.60517...

I am pretty sure I mentioned I am not a math wiz....I can't understand this at all.....thanks for the brain dump though...

[Herr Mensch 0]

If you are not a math wiz, then "working out" a natural logarithm is going to be next to impossible for you. Trust me, I'm a math wiz and I can't do it by hand. what you are thinking about is a logarithmic progression for tournament scoring, which winds up emphasizing first-place finishes, while consistently high finishers who never hit the big one are left out in the cold. a geometric progression is nearly as bad.A progression like dna4ever described rewards consistently good players. A one-hit wonder who rides a hot rush of cards to a single first-place and rarely ever cashes otherwise doesn't unfairly benefit over someone with a half-dozen top 20 finishes.I would assume dna uses a spreadsheet or similar setup to keep track of the N.O., perhaps he could share the file?Mensch