
Magnum666
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man this laydown is sick....unless cardplayer isn't telling the whole story (4 to a flush on the board or something) i guess he put grinder on 7-8? yikes.Date / Time: 2006-01-31 14:36:00Title: Don Mullis Makes A Big LaydownLog: With a board of J-6-4-9-5, Don bets $50,000 into a pot of of around $250,000. Michael Mizrachi reraises $500,000 more. Mullis goes into the tank and finally calls the clock on himself (this seems to be the trend today). He finally lays down pocket jacks face-up. "The Grinder" mucks his cards and rakes the pot.
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you've got 300 bb, so it looks sufficient. The general rule though is if you lose 100 bb ($200) move down a level to .5/1 and build back up to $600 before continuing at 1/2. Do this and you should be fine.
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oops it's already been answered...damn you guys are fast
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Since there is only one Ace remaining in the deck, the chances are pretty slim:On the flop: 6.25%On the turn: 2.08%On the river: 2.08%So the total chance of the Ace falling somewhere on the board is 10.42%Hope this helps....
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I've been playing limit .5/1 for a while now, averaging a little over 5 bb/100, and I'm planning on moving up to 1/2. As for the competion, is it noticeably tighter at 1/2? I'm wondering if it's just more profitable to keep three tabling at the .5/1 tables if the fish are much more prevalent there.As for which site, all of my play has been at Empire/Party.Thanks for any info.
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poker tracker question (probably simple)
Magnum666 replied to Magnum666's topic in General Poker Forum
thanks guys...that was even simpler than i thought it would be -
Quick and probably simple poker tracker question...I've got a bunch of NL $25 hands, and a bunch of $.5/$1 limit hands, how can I filter them so that when I look at the profit/loss by starting hand data under the general info screen it gives me only the data for the $.5/$1 hands?I'd like to see my won/loss info by starting hand for limit, but they're skewed by the NL hands I've played. I assume there's a way this can be done, any info would be great.
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Poor Daniel,First off, he's losing his shirt at the WSOP and the Greenstein games thus far, and now some nobody is giving him shit at the no-limit shoot out:2005-06-17 12:52:00 Title: Some Notes From the Early Going Log: There is no shortage of action here in the early going. Some big names have already been sent to the rail, including yesterday's $5,000 No-Limit Hold'em Champion T.J. Cloutier, Sammy Farha, and Mimi Tran. There is quite a feud brewing between Daniel Negreanu and an unknown player in Seat 2 at his table. Shortly after arriving at the table, Negreanu asked his unknown opponent,
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LOL, that IS sick!What's the url?Thanks
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luckiest thing thats happened to me in a while
Magnum666 replied to 93transam's topic in General Poker Forum
Two hands after being big blind you were small blind? Hmm..... -
More like 1/60,000 No I think it is 1 in 30,000.... the odds of the second guy getting aces are (2/50)*(1/49) = 1225.Remember, there are two aces remaining when he receives his first card, and one remaining when he receives the second.I stand humbly corrected. :oops:I think the correct odds is like 1/270725. You need to take the fact that YOU drew AA in the first place.Thus, making the equation (4/52)x(3/51)x(2/50)/(1/49).But I don't think you factored in the fact that this is a 10 handed game. 1/270k would be the odds of AA vs AA if you were heads up.
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Just saw this, very useful link
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Well, the odds of getting a pocket pair are lower than getting two non-paired cards, because one of the cards you are looking for is gone already. for exampe, if your first card is an A, you have a 3/51 chance of the second card being an A, whereas if you were looking for, say AK, and the first card was an A, you have a 4/51 chance of getting the King since they all still remain in the deck.So, the odds of getting any pocket pair are 3/51, or 1/17. And since there are 13 different numbered cards, the odds of getting AA are 1/17 * 1/13 = 221.Hope this helps...
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More like 1/60,000 No I think it is 1 in 30,000.... the odds of the second guy getting aces are (2/50)*(1/49) = 1225.Remember, there are two aces remaining when he receives his first card, and one remaining when he receives the second.
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in a 10 handed game i came up with about 1 in 30,000. my math could be off a bit though...